Question

a simple random sample from a population with a distribution of 97 body temperatures has x equal 98.40 and S equals 0.65 f construct a 98% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

? f <o<?f round to two decimal places as needed

12. Panda games showing substance use were observe and the duration of times of gameplay and seconds listed below the design of the study Justified the assumption that the sample can be treated as a simple random sample use the sample that constructing a 80% confidence interval estimate of the standard deviation of the duration times of gameplay assume that this sample was obtained from a population with normal distribution

4,729 4,092 4,381 3,948 4,424 4,203 4,212 4,960 4,234 5,000 3,833 4,676

the confidence interval estimate is? sec<o < ? sec
round to one decimal place as needed

Answer 1

Given that: - n = 97 s = 0.65 98% confidence internal for std dev (squareroot (n - 1) s^2/chi^2 alpha/2 < sigma < squareroot (n - 1) s^2/chi^2 1 - alpha/2) implies (squareroot (97 - 1) (0.65)^2/chi^2_0.01 < sigma < squareroot (97 - 1) (0.65)^2/chi^2_0.99) implies (squareroot 40.56/131.1412 < sigma < squareroot 40.56/66.7299) implies (0.5561 < sigma < 0.7796) implies Lower limit = 0.5561 Upper limit = 0.7796 \r\n Ans) Given that n = 12 x (x - 4)^2 4729 114244 4092 89401 4381 100 3948 196249 4424 1089 4203 85344 4212 32041 4960 323761 4234 24649 5000 370881 3833 311364 4676 81225 x = sigma x_i/n = 4391 S = squareroot sigma (x_i - mu)^2/n - 1 = squareroot 1580848/12 - 1 S = 379.0356 80% confidence interval for std dev (squareroot (n - 1) S^2/chi^2_alpha/2 < sigma < squareroot (n - 1) S^2/chi^2_(1 - alpha/2)) \r\n squareroot (12 - 1)