Homework Answers
let the time t1 = 4.9 minutes
velocity v1 = 0.84c
velocity v2 = 0.91c
Lorentz factors for v1 and v2 are:
γ₁ = 1/√(1−(v1/c)²) = 1.843
γ₂ = 1/√(1−(v2/c)²)= 2.41
The proper time is the time measured by the person filling her car (t′) is stated to be the same for both observations, so
t′ = t₁/γ₁ = t₂/γ₂
=> t₁/γ₁ = t₂/γ₂
=> t₂ = t₁(γ₂/γ₁) = 4.9*(2.41/1.843) = 6.41 min
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