A baseball pitcher can throw a ball with a speed of 70 m/s . He is in the back of a pickup truck that is driving away from you. He throws the ball in your direction, and it floats toward you at a lazy 10 m/s
The ball has two velocities (i) given by the truck in whichthe pitcher is travelling., vt
+(ii) the velocity given by the pitvher, vp = 70 m/s
Both are along the same line but in opposite direction.
Resultant Velocity of the ball,
Vb = Vp - Vt
Hence, Vt =Vp - Vb = 70 - 10 = 60 m/s
ANSWER :
Truck carrying pitcher is moving away from me.
Ball is thrown by the pitcher from the moving truck towards me at a speed of 70 m/s.
Ball in reality travels at a speed of 10 m/s towards me.
This is because of movement of truck and ball are in opposite directions.
Let speed of truck be V m/s. So, ball acquires the same speed and direction.
If ball is thrown in my direction at 70 m/s and it is moving away from me at V m/s, then,
ball ’s real speed towards me = 70 - V m/s
But it is noted as 10 m/s.
So,
70 - V = 10
=> V = 70 - 10 = 60 m/s.
So, speed of truck = 60 m/s (ANSWER).
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