what is the magnitude of the angular acceleration if the eye?
Δθ = 20 /2 = 10 deg = 10 *pi /180 = pi /18 rad
ωi = 0 and Δt = 68.6/2 = 34.3 ms =34.3 *10^-3 sec
Δθ = ωi *Δt + 1/2*α* Δt^2
pi /18 = 0 + 0.5*α * (34.3 *10^-3)^2
from here α ≈ 296.701 rad/s2
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