Question

All numbers to the 4th decimal place please!

LI Content Lens or mirror An object is held 85.6 cm away from a mirror. The mirror has a focal length of 49.7 cm. A.) Determine the image distance. B.) Determine the magnification. C.) If the object is 5 cm long, determine the image height. D.) Which of the following are true about the image? Choose all that apply. The image is inverted. The image is real. The image is upright. The image is virtual. E.) Which of the following are true about the mirror? Choose all that apply. The mirror is converging. The mirror is convex. The mirror is diverging. The mirror is concave. Minimum focal length of your eye Each of your eyes has a lens in it. This lens can change its shape and hence its focal length. By changing the focal length you are able to focus on an object based on how far away it is from you. For this problem you will determine the minimum focal length of your eye. A. Hold an object out in front of you at arm's length. Close one eye and bring the object towards your eye and determine how close it can be to your eye and still be in focus. B. The average human eye has an image distance of 1.7 cm. In other words, it is 1.7 cm from the lens in your eye to the retina. Using this information and your answer to A, determine the minimurr focal length of your eye. Also determine the magnification for this situation. FOCAL LENGTH = MAGNIFICATION =

Answer 1

The focal length of the mirror is the a Connex mirrar. A = - 8s. 6 CA . f = 99.7 em. : = $the *, V=(-( is = 31.49 en = 3444 . 31-4436 em. : image distance is = 31.49am Magnification - - - - 31-4436 = 0.3673 B) - 85.6 ex Image height = object height X-tu) = 5 x 0.36737 $85 . = 1.8365cm o the imare in upright The image is virtual. The witno The mirran is diverging mirrar y connex. X