Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm...
Use the thin lens equation to solve problems 14 –18.
14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification.
15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification.
16. An object is 10 cm high and is placed 12 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification.
17. An object is 10 cm high and is placed 30 cm in front of a diverging lens of focal length –20 cm. Determine the image distance, the image height and the magnification.
18.An object is 10 cm high and is placed 15 cm in front of a diverging lens of focal length –20 cm. Determine the image distance, the image height and the magnification.
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Use the thin lens equation to solve problems 14 –18.
14. An object is 10 cm...
Use ray diagrams to solve problems 10 –13. 10. An object is 10 cm high and...
Use ray diagrams to solve problems 10 –13. 10. An object is 10 cm high and is placed 30 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 11. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 12. An object is 10 cm...
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
(4%) Problem 18: An object of height 2.9 cm is placed 29 cm in front of...
(4%) Problem 18: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 15 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
An object is located at a distance of 6 cm from a thin converging lens with...
An object is located at a distance of 6 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 4 cm from the converging lens and 10 cm from the object. The diverging lens has a focal length of -3 cm. Note: To handle a multiple lens system, we treat them independently. We first find the image created by the first lens. We then use the image from the first lens to act...
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens...
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens having a focal length of 40.3 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position cm magnification...
ASAP please. 3. An object is placed at 10 cm from a thin converging lens of...
ASAP please.
3. An object is placed at 10 cm from a thin converging lens of focal length f. Its image is formed 30 cm from the lens on the same side as the object. (20 points) (a) What is the focal length? (4 points) (b) What are the magnification of the image, the orientation of the image (upright/inveredy (2+2 (c what kind ofimage is formed (reduced/magnified, real/virtual, and uprigh?1nvertedy? (2+2 (d) If the lens is replaced by a thin...
Problem 3: An object of height 2.8 cm is placed 26 cm in front of a...
Problem 3: An object of height
2.8 cm is placed 26 cm in front of a diverging lens of focal length
16 cm. Behind the diverging lens, and 11 cm from it, there is a
converging lens of the same focal length.
a) Find the location of the final image, in centimeters beyond
the converging lens (such that a negative answer would indicate the
final image is on the same side of the converging lens as the
object).
b) What...
14. An object is 2 cm from a concave (diverging) lens. The resulting height of the...
14. An object is 2 cm from a concave (diverging) lens. The resulting height of the virtual image is half as large as the the height of the object. What is the focal length of the lens? (Hint: Use the information given to determine the lateral magnification, and from that determine the image distance. The use the thin lens equation.) (A) - cm (B) - cm (C) -1 cm (D) –2 cm
An object is placed 45 cm to the left of a converging lens of focal length...
An object is placed 45 cm to the left of a converging lens of focal length 17 cm. A diverging lens of focal length −29 cm is located 11 cm to the right of the first lens. (Consider the lenses as thin lenses). a) Where is the final image with respect to the second lens?cm b) What is the linear magnification of the final image?
(4%) Problem 18: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 15 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
ASAP please.
3. An object is placed at 10 cm from a thin converging lens of focal length f. Its image is formed 30 cm from the lens on the same side as the object. (20 points) (a) What is the focal length? (4 points) (b) What are the magnification of the image, the orientation of the image (upright/inveredy (2+2 (c what kind ofimage is formed (reduced/magnified, real/virtual, and uprigh?1nvertedy? (2+2 (d) If the lens is replaced by a thin...
Problem 3: An object of height
2.8 cm is placed 26 cm in front of a diverging lens of focal length
16 cm. Behind the diverging lens, and 11 cm from it, there is a
converging lens of the same focal length.
a) Find the location of the final image, in centimeters beyond
the converging lens (such that a negative answer would indicate the
final image is on the same side of the converging lens as the
object).
b) What...
14. An object is 2 cm from a concave (diverging) lens. The resulting height of the virtual image is half as large as the the height of the object. What is the focal length of the lens? (Hint: Use the information given to determine the lateral magnification, and from that determine the image distance. The use the thin lens equation.) (A) - cm (B) - cm (C) -1 cm (D) –2 cm
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