An object is located at a distance of 6 cm from a thin converging lens with...
An object is located at a distance of 6 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 4 cm from the converging lens and 10 cm from the object. The diverging lens has a focal length of -3 cm. Note: To handle a multiple lens system, we treat them independently. We first find the image created by the first lens. We then use the image from the first lens to act as the object for the second lens.
Use the thin lens equation (1/f = 1/s' + 1/s) to predict the following:
(a) Location of the image?
(b) Magnification of the image (including inverted versus non-inverted)?
(c) Real or virtual?
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An object is located at a distance of 6 cm from a thin
converging lens with...
An object is on the left side of a thin converging lens. The object is located...
An object is on the left side of a thin converging lens. The object is located at a distance of 6 cm away from a thin converging lens with focal length of 2 cm. Use the thin lens equation (1/f = 1/s' + 1/s) to predict the following: (a) Location of the image? (b) Magnification of the image (including inverted versus non-inverted)? (c) Real or virtual? Draw diagram please!
(2) An object is located at a distance of 4 cm from a thin converging lens...
(2) An object is located at a distance of 4 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 3 cm from the converging lens and 7 cm from the object. The diverging lens has a focal length of -2 cm. Use the thin lens equation to predict the following (a) Location of the final image? to the object? (c) Is the final image real or virtual?
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
A converging lens with a focal length of 4.2 cm is located 20.7 cm to the...
A converging lens with a focal length of 4.2 cm is located 20.7 cm to the left of a diverging lens having a focal length of -11.5 cm. If an object is located 9.2 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? Submit Answer Tries 0/10 What is the magnification? Submit Answer Tries 0/10 Also determine, with...
A converging lens with a focal length of 6.0 cm is located 24.0 cm to the...
A converging lens with a focal length of 6.0 cm is located 24.0 cm to the left of a diverging lens having a focal length of -13.0 cm. If an object is located 11.0 cm to the left of the converging lens, locate and describ completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? 63.81 cm Submit Answer Incorrect. Tries 3/10 Previous Tries What is the magnification? Submit Answer...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a fo...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
ASAP please. 3. An object is placed at 10 cm from a thin converging lens of...
ASAP please.
3. An object is placed at 10 cm from a thin converging lens of focal length f. Its image is formed 30 cm from the lens on the same side as the object. (20 points) (a) What is the focal length? (4 points) (b) What are the magnification of the image, the orientation of the image (upright/inveredy (2+2 (c what kind ofimage is formed (reduced/magnified, real/virtual, and uprigh?1nvertedy? (2+2 (d) If the lens is replaced by a thin...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A 20 cm tall object is located 70 cm away from a diverging lens that has...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
(2) An object is located at a distance of 4 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 3 cm from the converging lens and 7 cm from the object. The diverging lens has a focal length of -2 cm. Use the thin lens equation to predict the following (a) Location of the final image? to the object? (c) Is the final image real or virtual?
A converging lens with a focal length of 4.2 cm is located 20.7 cm to the left of a diverging lens having a focal length of -11.5 cm. If an object is located 9.2 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? Submit Answer Tries 0/10 What is the magnification? Submit Answer Tries 0/10 Also determine, with...
A converging lens with a focal length of 6.0 cm is located 24.0 cm to the left of a diverging lens having a focal length of -13.0 cm. If an object is located 11.0 cm to the left of the converging lens, locate and describ completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? 63.81 cm Submit Answer Incorrect. Tries 3/10 Previous Tries What is the magnification? Submit Answer...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
ASAP please.
3. An object is placed at 10 cm from a thin converging lens of focal length f. Its image is formed 30 cm from the lens on the same side as the object. (20 points) (a) What is the focal length? (4 points) (b) What are the magnification of the image, the orientation of the image (upright/inveredy (2+2 (c what kind ofimage is formed (reduced/magnified, real/virtual, and uprigh?1nvertedy? (2+2 (d) If the lens is replaced by a thin...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
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