Question

2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale is often expressed as (1 cm: 5 cm). Using your ray diagram, measure the image distance (s') and use it and the given object distance to calculate the magnification of the image. State whether the image is erect or inverted, and whether it is real or virtual. 3. Solve Question 2 analytically; i.e., use the thin-lens equation to find the position of the image. Describe the image completely; i.e., give its distance from the lens, state whether it is erect or inverted, and indicate whether it is real or virtual. Find the magnification of the lens.

Answer 1

ineage Object U=30 5 Valsy V 215cm

using lens formula

1/f = 1/v - 1/u

1/ 10 = 1/v + 1/30

v = 15 cm

image must be real, virtual and diminished

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