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Prob.l. A rectangular magnetic core shown in the below Fig, has square cross-section of area 16 cm. An air-gap of 2 mm is cu
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Given area of cross section 16 * 10-4 m A. = 16 cm

length of airgap is , 3 2 тm — 0.2 ст -2 * 10- b. 3 т

N=1000 turns

airgap flux Pg = 4 mWb

relative permeability , = 2000

let the side is square cross section be 's'

s2 = A, = 16 cm

s=\sqrt{16}=4\: \: cm

s=4\: \: cm marked in figure shown

N 1000 s=4cm 2 mm Mean length of core l -20 cm 25 cm

from the circuit mean length of the core is

l=2*(20-\frac{s}{2}-\frac{s}{2})+(25-\frac{s}{2}-\frac{s}{2})+(25-\frac{s}{2}-\frac{s}{2}-l_{g})

l=2*(20-\frac{4}{2}-\frac{4}{2})+(25-\frac{4}{2}-\frac{4}{2})+(25-\frac{4}{2}-\frac{4}{2}-0.2)

l=2*(16)+(21)+(20.8)=73.8\: \: cm

l=73.8\: \: cm=73.8*10^{-2}\: m

Now reluctance of the core is

\Re _{c}=\frac{l}{A\mu_{o} \mu _{r}}=\frac{73.8*10^{-2}}{16*10^{-4}*4\pi *10^{-7}*2000}=183525.54\: \: AT/Wb

\Re _{c}=183525.54\: \: AT/Wb

Reluctance of airgap is

2 * 10-3 994718.39 AT/Wb %3D 16 * 10-4 * 4T * 10-7 Alofr

R, = 994718.39 AT/Wb

Now equation for airgap flux is given as

\varphi _{g}=\frac{NI}{\Re _{c}+\Re _{g}} where 'I is exciting current needed in the coil

I=\frac{\varphi _{g}*(\Re _{c}+\Re _{g})}{N}=\frac{4m*(183525.54+994718.39)}{1000}

\mathbf{I=4.713\: \: A} is the current needed

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