Heat absorbed by the aquous mixture(q1)
q1 = m × ∆T × C
m = mass of quous mixture, 407.4g
∆T = Temperature difference of aquous mixture , 5.6℃
C = specific heat capacity of aquous mixture , 4.184J/g℃
q1 = 407.4g × 5.6℃ × 4.184J/g℃
q1 = 9545.5J
Heat absorbed by the caloriemeter(q2)
q2 = ∆T × C
∆T = temperature difference of caloriemeter, 5.6℃
C = heat capacity of calorimeter, 17.2J/℃
q2 = 5.6℃ × 17.2J/℃
q2 = 96.32J
∆H = - (q1 + q2)
∆H = - ( 9545.5J + 96.32J)
∆H = -9641.8J
∆H = - 9.64 kJ
please show work ING ISDN HIV382 100 14.8= 35.2 2500424 2074 Page 3 of 9 solution...
show all the steps please.
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