Use Hess' Law to calculate the ΔH for the following reaction from the data given below.
Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l) ΔH = _________
Na2CO3(s) → CO2(g) + Na2O(s) ΔH = 319.8 kJ
2NaCl(aq) + H2O(l) → 2HCl(aq) + Na2O(s) ΔH = +348.0 kJ
Use Hess' Law to calculate the ΔH for the following reaction from the data given below....
Applying Hess’s Law, from the enthalpies of reactions, 2NaCl(s) + H2O(l) --> 2HCl(g) + Na2O(s) ΔH = + 507.31 kJ NO(g) + NO2(g) + Na2O(s) --> 2NaNO2(s) ΔH = − 427.14 kJ NO(g) + NO2(g) --> N2O(g) + O2(g) ΔH = − 42.68 kJ 2HNO2(l) --> N2O(g) + O2(g) + H2O(l) ΔH = + 34.35 kJ Calculate the enthalpy change (ΔHrxn) for the reaction: HCl(g) + NaNO2(s) --> HNO2(l) + NaCl(s) (You should show work to get credit) 5-Magnesium burns...
a) Using the Hess Law and the thermochemical equations below, MgO(s) + + 2HCl(aq) ------> MgCl2(g) + H2O(l) ΔHrxn = -111.7 kJ/mol Mg(s) + 2 HCl(aq) ------> MgCl2(g) + H2(g) ΔHrxn = -548.3 kJ/mol H2(g) + 1/2 O2(g) ------> H2O(l) ΔHrxn = -142.9 kJ/mol find the heat of reaction of the following: Mg(s) + 1/2 O2(g) ------> MgO(g) ΔHrxn = ? b) If the theoretical enthalpy of this reaction is -602 kJ/mol, calculate the percent error
Part A) What is ΔH∘rxn for the following chemical reaction? CO2(g)+2KOH(s)→H2O(g)+K2CO3(s) You can use the following table of standard heats of formation (ΔH∘f) to calculate the enthalpy of the given reaction. Element/ Compound Standard Heat of Formation (kJ/mol) Element/ Compound Standard Heat of Formation (kJ/mol) H(g) 218 N(g) 473 H2(g) 0 O2(g) 0 KOH(s) −424.7 O(g) 249 CO2(g) −393.5 K2CO3(s) −1150kJ C(g) 71 H2O(g) −241.8kJ C(s) 0 HNO3(aq) −206.6 Express the standard enthalpy of reaction to three significant figures and...
(Please explain) Hess Law delta H Manipulate the data provided to find the ΔHrxnfor the reaction: CH4(s) + 2 O2(g) →CO2(g)+ 2 H2O(l) (1) 2 CH4(g)+ 3 O2(g) →2 CO(g) + 4 H2O (l) ΔH= −1215 kJ (2) 2C + O2(g) →2 CO(g) ΔH= −221 kJ (3) C (s) + O2(g) → CO2(g) ΔH= −394 kJ I have solved it myself but I am not sure of the answer I have gotten. my answer was about -228.5kj
Help me get the answer -78.5 2) Use Hess's law to calculate the enthalpy of the reaction below using the following information. [Ans: -78.5] HCl(g) + NaNO2(s) → HNO2(1) + NaCl(s) AH=? 2NaCl(s) + H2O(l) + 2HCl(g) + Na2O(s) NO(g) + NO2(g) + Na2O(s) - 2NaNO3(s) NO(g) + NO2(g) N2O(g) + O2(g) 2HNO2(1) - N2O(g) + O2(g) + H2O(1) AH = 507 kJ AH = -427 kJ AH = -43 kJ AH = 34 kJ
Using the Hess Law and the thermochemical equations below, MgO(s) + + 2HCl(aq) ------> MgCl2(g) + H2O(l) ΔHrxn = -111.7 kJ/mol Mg(s) + 2 HCl(aq) ------> MgCl2(g) + H2(g) ΔHrxn = -548.3 kJ/mol H2(g) + 1/2 O2(g) ------> H2O(l) ΔHrxn = -142.9 kJ/mol find the heat of reaction of the following: (0.25 pt.) Mg(s) + 1/2 O2(g) ------> MgO(g) ΔHrxn = ? b) If the theoretical enthalpy of this reaction is -602 kJ/mol,...
Imported From Sa... 4. Use Hess' Law to calculate the enthalpy change (AHY) for this reaction: (12 pts.) 6C) + 6H21 309) CH120) using the following equations: A. Cw+ O2(g) → CO2(0) B. Hag) + 1/2O2(g) → H2O(g) C. CoH12O6 + 602(0)+ 6CO2(g) + 6H2O D. H2O → H2O(g) AH'= -393.5 kJ SH-241.8kJ AH = -2803.0 kJ AH = +40.71 kJ Why is this change in enthalpy given the term AHY? (3 pts.)
Use Hess' law and the data below to calculate AG, in kJ, for the following reaction: NO(g) + O (9) NO2 (g), AG° = ? 2 03 (9) - 3 O2 (g), AG° = +489.6 kJ 02 (9) 20 (9), AGⓇ = +463.4 kJ NO(g) + O2 (9) - NO2 (g) + O2 (g), AG° = -199.5 kJ QUESTION 14 Calculate AG for the following reaction, in kJ, at 0 °C under the following non-standard conditions shown below. 2 Hgo...
Calculate ΔH for the following reaction, CaO(s) + CO2(g) → CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) → 2 CaO(s) ΔH = -1270.2 kJ C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) ΔH = -2413.8 kJ A compound contains C, H and O as the elements. A 20.0 g-sample is comprised of 1.34 g H and also 8.00 g of C. What...
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol