Help me get the answer -78.5 2) Use Hess's law to calculate the enthalpy of the...
Applying Hess’s Law, from the enthalpies of reactions, 2NaCl(s) + H2O(l) --> 2HCl(g) + Na2O(s) ΔH = + 507.31 kJ NO(g) + NO2(g) + Na2O(s) --> 2NaNO2(s) ΔH = − 427.14 kJ NO(g) + NO2(g) --> N2O(g) + O2(g) ΔH = − 42.68 kJ 2HNO2(l) --> N2O(g) + O2(g) + H2O(l) ΔH = + 34.35 kJ Calculate the enthalpy change (ΔHrxn) for the reaction: HCl(g) + NaNO2(s) --> HNO2(l) + NaCl(s) (You should show work to get credit) 5-Magnesium burns...
Calculate the enthalpy of the reaction 2NO(g) + O2(g)2NO2(g) Hess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." It is important to recall the following rules: given the following reactions and enthalpies of formation: 1. ¢ N2(g) + O2(g)+NO2(g), AH; = 33.2 kJ 2. N2(g) + O2(g) NO(g), AHB = 90.2 kJ 1. When two reactions are added, their enthalpy values are...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Ho ilacer e trunschpl Use Hess's Law to calculate the standard enthalpy (AHº) for the foll standard enthalpy (AH) for the following reaction inolonce to the on an C(s) + O2(g) → CO(g) given the following two equations. C(s) +502(9) – co(9) AH° = -110.5 kJ CO2(g) – CO(g) +502(9) AH° = +283.0 kJ [15]
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
- + ~ [ Fit to page 1 11. Hess's Law - Calculate the enthalpy for the following reaction (20 pts) 11.1. NzH4 (1) ► N; (g) + 2H; (g)AH = ? Consider that N2H4 (1) +02 → N(g) + H20 (g), AH = -543.2 kJ 2H2(g) + O2 → H20 (g), AH = -241.8 kJ
Use Hess' Law to calculate the ΔH for the following reaction from the data given below. Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l) ΔH = _________ Na2CO3(s) → CO2(g) + Na2O(s) ΔH = 319.8 kJ 2NaCl(aq) + H2O(l) → 2HCl(aq) + Na2O(s) ΔH = +348.0 kJ
4. Using Hess's Law, calculate the enthalpy of formation of potassium chlorate: K (s) + Cl2 (g) + 3/2 02 (g) →KCIO: (s) AH = ? kJ Based on the enthalpy changes for the following reactions: 2 K (8) + Cl2 (g) → 2 KCI (3) AH - 874.0 kJ KCIO: (s) + 3 Mg (8) ► KCl (s) + 3 Mg0 (8) AHxx. - 1852.0 kJ MgO (3) ► Mg (s) + O2(g) AHan = +602.0 kJ
Using Hess's Law, determine the enthalpy change of the following reaction. CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) C(s) + O2(g) --> CO2(g) AH = -393.5 kJ/mol S(s) + O2(g) --> SO2(g) AH = -296.8 kJ/mol C(s) + 25(s) --> CS2(8) AH = +87.9 kJ/mol -899.2 kJ O-778.2 kJ -602.4 kJ - 1075.0 kJ