Part A
∆H = -114 kj
Part B
∆H = -2552 kj
Calculate the enthalpy of the reaction 2NO(g) + O2(g)2NO2(g) Hess's law states that "the heat released or absorbed in a...
Calculate the enthalpy of the reaction 2NO(g) + O2(g) +2NO2 (g) given the following reactions and enthalpies of formation: 1;N, (g) +0,(g)NO,(g), AH = 33.2 kJ 2 N2(g) + O2(g) →NO(g), AHg = 90.2 kJ Express your answer with the appropriate units. View Available Hint(s) AH'- Value Units Submit
Part A Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation: 12N2(g)+O2(g)→NO2(g), ΔH∘A=33.2 kJ 12N2(g)+12O2(g)→NO(g), ΔH∘B=90.2 kJ Express your answer with the appropriate units. Part B Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔH∘A=+2035 kJ 2B(s)+3H2(g)→B2H6(g), ΔH∘B=+36 kJ H2(g)+12O2(g)→H2O(l), ΔH∘C=−285 kJ H2O(l)→H2O(g), ΔH∘D=+44 kJ Express your answer with the appropriate units.
Learning Goal: To understand how to use Hess's law to find the enthalpy of an overall reaction. Correct The change in enthalpy, AH, is the heat absorbed or produced during any reaction at constant pressure. Hess's law states that ? H for an overall reaction is the sum of the values for the individual reactions. For example, if we wanted to know the enthalpy change for the reaction PartB What is the enthalpy for reaction 1 reversed? Express your answer...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
(D) SNU29) + 12 + 2HNO3(14) + NU19) 8) Determine the overall reaction, using Hess's Law to calculate the enthalpy of the reactions from the reaction step mechanism. Step1: 300,(9) ► N269) + 02(g) AH = -99.6 kJ Step 2: H2O(l) → H2(g) + 02(9) AH; = +285.8 kJ Step 3: Hz(9) + N2(g) + 3 02(9) → 2 HNO3(aq) AH; = -414.8 kJ Step 4: N2(g) + 02(9) ► NO(9) AH; = 90.2 kJ
Using Hess's Law, determine the enthalpy change of the following reaction. CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) C(s) + O2(g) --> CO2(g) AH = -393.5 kJ/mol S(s) + O2(g) --> SO2(g) AH = -296.8 kJ/mol C(s) + 25(s) --> CS2(8) AH = +87.9 kJ/mol -899.2 kJ O-778.2 kJ -602.4 kJ - 1075.0 kJ
21 Use Hess's Law to calculate the enthalpy change for the reaction: Wo3(s)+3H2(g)-W(s)+3H20(g) Eqn 1: 2W(s)302(g) 2WO3(s) AH -1685.4 kJ/mol Eqn 2: 2H2(g) O2(g)2H20(g) AH -477.84 kJ/mol Give your answer as just a number without the assumed units (kJ/mol)
Help me get the answer -78.5 2) Use Hess's law to calculate the enthalpy of the reaction below using the following information. [Ans: -78.5] HCl(g) + NaNO2(s) → HNO2(1) + NaCl(s) AH=? 2NaCl(s) + H2O(l) + 2HCl(g) + Na2O(s) NO(g) + NO2(g) + Na2O(s) - 2NaNO3(s) NO(g) + NO2(g) N2O(g) + O2(g) 2HNO2(1) - N2O(g) + O2(g) + H2O(1) AH = 507 kJ AH = -427 kJ AH = -43 kJ AH = 34 kJ
Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) Given the following reactions and enthalpies of formation: N2(g) + 2O2(g)→ 2NO2(g), ΔH∘ = 66.4kJ N2(g)+ O2(g)→ 2 NO(g), ΔH∘=180.4 kJ Please explain the steps as well!