Question

U MCHALK GO A 4.00-g bullet is moving horizontally with a velocity of 255 m/s, where the +sign indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, e indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1150 g, and its velocity is +0.550 m/s after the bullet passes through it. The mass of the second block is 1530 g. (a) What is the velocity of the second block after the bullet embeds itself? (b) Find the ratio of the total kinetic energy after the collisions to that before the collisions. +355 m/s Block 1 Block 2 (a) Before collisions +0.550 m/s Vblock 2 mblock 1 = 1150 g mblock 2 = 1530 g mbullet = 4.00 g (b) After collisions PROBLEM 42

Answer 1

mivi ca. By conservation of momenten ma ve 2 m, vt (M + mp) V 2 V2 4X100x355-1.150xo.sso 1.530 + 4x103 20.513 misi 2 2 M₂ + MB 1:42-0.6325 1.534 ri After K.E before KE 2 Mivt + m2 + m ) Vt, ko Einhore Movie K. Einfter myk Watnes uz - m, vt + m2 + Mg) v² moviola & mout - 1-150x0.ssó + (1.530 +4x132)x0.5132 441038552 2 0.347875 + 0.403701 504.1 2 1.4909X163