ANSWER:
Ans:
1)sample proportion
=58/300
=0.1933
Test statistic:
z=(0.1933-0.1667)(0.1667*(1-0.1667)/300)
z=1.239
critical z value=+/-1.96
Fail to reject the null hypothesis.
There is not sufficient evidnece to conclude that the die is not fairly balanced.
2)
lower cut off=0.1667-1.96*(0.1667*(1-0.1667)/300)
=0.1245
upper cut off=0.1667-1.96*(0.1667*(1-0.1667)/300)
=0.2089
when true p=0.25
z(0.1245)=(0.1245-0.25)(0.25*(1-0.25)/300)
=-5.02
z(0.2089)=(0.2089-0.25)(0.25*(1-0.25)/300)
=-1.645
P(type II error)=P(-5.02<z<-1.646)
=P(z<-1.646)-P(z<-5.02)
=0.0498-0.0000
=0.0498
I need answer part 2 1. A die is rolled 300 times; it lands five 58...