Question

Using ch 8 techniques from the 9th edition Svoboda, Dorf Into to Electric Circuits solve: (see photo for problem statement.)

-3モ assume VEo.

Answer 1

Transforming the circuit into s -domain using super position principle, when voltage at inverting terminal is acting alone, v_0_1 (s) = -4/4 (v_g (s)) v_0_1 (s) = -v_g (s) when voltage at non inverting terminal is acting alone, v_p (s) = v_g (s) (2)/2 + 4/s v_p (s) = s v_g (s)/s + 2 The out put v_0_2 (s) = (1 + 4/4) v_p (s) v_0_2 (s) = 2s/s + 2 v_g (s) The Total output V_0 (s) = v_0_1 (s) + V_0_2 (s) = -v_g (s) + 2s/s + 2 v_g (s) v_0 (s) = (-1 + 2s/s + 2) v_g (s) v_0 (s) = (s - 2/s + 3) v_g (s) given v_g (t) = 2 e^-3t v_g (s) = 2/s + 3 v_0 (s) = (s - 2/s + 2) (2/s + 3)