Question

Not sure of my answers

In an observational study of teams fishing for lobster in a particular area, the average distance separating traps (in meters) for a sample of six teams was measured. Data are shown in the accompanying table Suppose you previously tested whether the average of the trap spacing measurements for the population of lobster fishermen in this area differs from 95 meters. Complete parts a through e 100100 90 101 92 105 a. There is concern that the trap spacing data do not follow a normal distribution. If so, how will this impact the test you conducted previously? O A. This will lead to rejecting the null hypothesis when it is true. O B. This will not impact the previous test. ° C. The inferences will not be valid. O D. This will lead to not rejecting the null hypothesis when it is false. b. Propose an altemative nonparametric test to analyze the data. Choose the correct answer below ๏ A. sign test of Ho-na 95 vs. Hai #95 B. sign test of Ho : η-95 vs. Ha, η > 95 ° C. rank test of Ho: η-95 vs. Ha : η > 95 OD. rank test of Ho:n-95 vs. Ha : η#95 c. Compute the value of the test statistic for the nonparametric test. d. Find the p-value of the test. p-value 688 (Round to three decimal places as needed.) e. Use α-0.10 and give the appropriate condusion. Do not reject H There is insufficient evidence that the median of the trap spacing measurements for the population of lobster fishermen in this area differs from 95 meters at 0.10

The whole data is the little table at the right upper corner

Answer 1

Given that,
population mean(u)=95
sample mean, x =98
standard deviation, s =5.7619
number (n)=6
null, Ho: μ=95
alternate, H1: μ!=95
level of significance, alpha = 0.1
from standard normal table, two tailed t alpha/2 =2.015
since our test is two-tailed
reject Ho, if to < -2.015 OR if to > 2.015
we use test statistic (t) = x-u/(s.d/sqrt(n))
to =98-95/(5.7619/sqrt(6))
to =1.275
| to | =1.275
critical value
the value of |t alpha| with n-1 = 5 d.f is 2.015
we got |to| =1.275 & | t alpha | =2.015
make decision
hence value of |to | < | t alpha | and here we do not reject Ho
p-value :two tailed ( double the one tail ) - Ha : ( p != 1.2754 ) = 0.2582
hence value of p0.1 < 0.2582,here we do not reject Ho
ANSWERS
---------------
a.
option:D
b.
null, Ho: μ=95
alternate, H1: μ!=95
c.
test statistic: 1.275
critical value: -2.015 , 2.015
decision: do not reject Ho
d.
p-value: 0.2582
e.
we do not have enough evidence to support the claim that avearge of trap spacing measurements
for the population of lobster fishermen in the area differ from the 95.