Question

(6) R An RLC circuit with resistance 160 2. capacitance 15 ur inductance 230 ml, frequency 60 Hz and peak voltage 36 V. Calculate the Satu litar RLC dengan rintangan 1602, kapasitans 15 UF, inchikrans 230 ml, frekuensi 60 Hz dan voltan puncak 36 V. Hitung (1) impedance. 7 = /163+C176.84-86.732 impedans. 183-642 (ii) phase angle between the current and the voltage. sudut fasa antara arus dan voltan. (iii) rms current. arus pmkd. (iv) average power dissipated in the resistor. kuasa purata lesap dalam perintang. 4A

Answer 1

I R C= 15uF. M - Ans - H 16002 ix Z2 = 230 mH Vm=36Z0y @ E ,X = 2Xf2 lay Z = R+ 6jXc) + j XL , Xc = t A 271fc z=160 - i + j2TfL Qafc = 160 - į + jQ7x60x230x173 271x60x15xloo = 160-290-132 = 160 - 317684 +38617 [z=(160-310132) 121 = 1160*+ 90.13.22 = 1831642 :: Magnituck of impedance . IZ1 =18316427

6 Im = Vm = Ž 36209 160-190.132 = 0.196229.39€ A. & phase angle between V&I, d = 29.39 -0° = 29.39° in phare angle beturen vetge a current (p=21:39] 19 (6) sms current , 0.196 = 0.139 A ms es mas corent, Tong = 0132 A er Koamnet Mars 34 = 25:46 V Average lower dissipated in the resistor, Prag - Yous Toms Card | = 4S, 6 x0-137x6x64) = 3:082 W 2. Average Power dissipated in the resistor, Sony = 3082 W]
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