Question

2 FeC204(H20)21s) + 3 K.C.O + H2CO + H2020-9---> KFe(C,05)(H2O) yellow salt green salt How many moles of KsFe(C(H20), (green Mass of green crystals= 2.61g

moles of yellow salt= 0.006386

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Answer #1

Reaction provided is 2 Fe C₂0₂ CH2012 (s) +3 kq C204 Cap) -> 2kz Fe (606) 3 Chaos). (Green salt) + H₂C₂O4 (ap) + H22 Cop) y p37 8 yield. % Yield & Esepelimental Yield xle Theoritical yoeld o Xloo 2.61 g xloo 3,139 (2.619 is mans of green clystals is

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Mass of green crystals= 2.61g moles of yellow salt= 0.006386 2 FeC204(H20)21s) + 3 K.C.O +...
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