Mass of green crystals= 2.61g moles of yellow salt= 0.006386 2 FeC204(H20)21s) + 3 K.C.O +...
With the completion of the determinations of % potassium, % iron, and % oxalate in the crystals, you may calculate the % water. The percentage compositionof the crystals, KxFe(C2O4)y · zH2O, has then been completely determined experimentally. The simplest formula (x,y,z) can now be calculated from the the percentage composition. Once the formula is know it is then possible to calculate the percent yield of product that was obtained in the preparation and purification of the crystals. From Part A:...
Equation given in lab manual Fe(C2O4)y-x + 3OH - ---> Fe(OH)3 + yC2O4-2 1. Moles of NaOh used to complete the reaction 2. Moles of iron(III) oxalate reacted 3. Moles of Fe+3 reacted 4. Grams of Fe+3 reacted 5. Percentage of Fe+3 in the KxFe(C2O4)y * zH2O green salt complex 6. Calculate the actual percentage of Fe+3 in K3(C2O4)3 * 3H2O 7. Percent error? Data: Mass of crystals 0.177g 40ml of distilled water used to dissolve the crystals Total volume...
3. What is the mole ratio of salt to water for the following compounds? Hydrate Salt Water CaCl2 - 2 H20 FeSO4 · 7 H20 Na2S2O3 - 5 H20 Ba(OH)2 8 H20 MnSO4 H2O 4. A student worked with a sample of ZnSO4.7H2O. a. How many atoms of each element are present? b. What is the stoichiometric ratio of salt to water? c. Calculate the percent of water in the hydrate. Show your work.
Match the neutralization reaction to the salt formed. A. NH4Cl , 2KOH + H2SO4 --->_+2 H20 ,NH4OH + HCI ------> + H20 ,Ca(OH)2 + 2 HNO3 ---> + 3H20 B. K2504 C. NH4 (NO3)2 D. Ca(NO3)2 E. KC In the titration of citric acid, the volume of 0.100 M NaOH to reach the equivalence point is 37 ml. How many moles of NaOH was used to neutralized the unbuffered citric acid? 0.000370 mol 0.0370 mol 0.370 mol 0.00370 mol
3 Cl2 + 6 KOH 5 KC - KCIOS - 3H30 a. How many moles of Cly have to react to produce 15 x 10 moles of KCIO3? b. How many grams of KCl are produced from the complete reaction of 3.0 moles of KOH? c. How many moles of Cly have to react to produce 5.40 x 103 g of H20? d. How many molecules of KOH have to react to produce 1.5 moles of H20? e. How many...
for problems 3-6, refer to the following balanced equation: 2C2H2(g) + 5O2(g) + 4CO2(g) + 2H2O(0) 3. How many moles of CO2 are produced when 18 moles of O2 reacts? 4. How many grams of water (H20) are produced from 8.4 moles of CH2?! 5. How many grams of O2 react with 7.32 g of CzHz? During an experiment, 5.19 g of oxygen (O2) reacted with excess C2Hz to produce 4.38 g of CO2. Determine the percent yield of CO2...
Use the References to a Using the equations below, how many moles of H20 are produced from 2.0 moles of Pb? 2Pb + 2HC2H2O2 +02- 2Pb(OH)C2H2O2 6Pb(OH)C2H3O2 + 2002- PB3(OH)2(CO3)2 + 2H2O + 3Pb(C2H302)2 0.33 0.67 O 2.0 1.3 Sg(s) + 8 O2(g) → SO2(g) 2 SO2(g) + O2(g) +2 SO3(g) SO3(g) + H200) —H2SO4(aq) If each step has a percent yield of 77.1%, how many grams of Sg are needed to produce 1.50 kg sulfuric acid? 637 g 1.07*10^3...
need a-g LAB VII. PRACTICE PROBLEMS NAME: SECTION: PART D. CHAPTER 4 PROBLEMS I) Reaction Stoichiometry, Limiting Reactant, Theoretical and Percent Yields a) For the equation Cu + C → Cu + Co, if 2.73 moles of C are reacted with an excess of Cu20, how many moles of CO would be produced? moles b) For the equation Co(NO3)3 + (NH4)2S → Co2S3 + NH4NO3, if 79.2 g of Co(NO3)3 are reacted with an excess of (NH4)2S, how many moles...
Please see attched. Please only do the circle and check questions.1 a, c, 2 a, b Stoichiometry Wor PAGE B) 1Na2SIOs (s)+ 8 HF(aq)H2SiF6 (aq)+ 2 NaF(aq)+3 H20 U) Vh.How many moles of !HIF are needed to react with 0300 mol of NasSi0,? b. How many grams of NaF form when 0.500 mol of HF reacts with excess Na Sit vć. How many grams of Na Si0, can react with 0.800 g of HF7 2. CsH120s (aq) 2 CH,OH [aq)...
Pre-Laboratory Assignment 1. Briefly describe the hazards associated with us ing the following (1) concentrated NH, solution 3. We can prepare the yellow coordination compound potassium tris(oxalato rhodate(lll), KIRh(,0)), by reacting potassiumn hexachlororhodatelli), KIRCI. and potassium oxalate, K 0,04 (1) Balance the chemical equation for this reac- tion, shown below. K(RhCi (aq) + K C20 (aq) → K[Rh(C2O4)3 (s. yellow) + KCl(aq) (2) If we combine 1 mol of KIRhClel with 1 mol of K C204, which compound is the...