Question

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LAB VII. PRACTICE PROBLEMS NAME: SECTION: PART D. CHAPTER 4 PROBLEMS I) Reaction Stoichiometry, Limiting Reactant, Theoretical and Percent Yields a) For the equation Cu + C → Cu + Co, if 2.73 moles of C are reacted with an excess of Cu20, how many moles of CO would be produced? moles b) For the equation Co(NO3)3 + (NH4)2S → Co2S3 + NH4NO3, if 79.2 g of Co(NO3)3 are reacted with an excess of (NH4)2S, how many moles of NH4NO, would be produced? moles c) For the equation (NH),CO, → CO2 + H2O + NH3, if 4.01 moles of (NH),CO, reacted, what is the theoretical yield of CO2? d) For the equation N2H4 → NH3 + N2, if the theoretical yield is 28.0 grams of N2, what mass in grams of N2H4, would have to react? e) For the equation FeS + HCl → FeCl2 + H2S, if 35.0g of FeS is added to 35.0g of HCl and allowed to react, what is the theoretical yield of H2S? f) Using the numbers from problem e) above, if 10.2 g of H2S were obtained in the lab (actual yield), what is the percent yield? g) How many grams of K C204, potassium oxalate, would contain 182 grams of pure potassium? a m mation and Solution Stoichiometry

Answer 1

♡ @ Cu O + C + 2 Cu + Co(Balanced reaction). As Cugo is in excess. So moles of co produced will depend o upon moles of c which is limiting. so, moles of co - 1 mol co Pooduce y 8.73 mol C I mol c reacted = 12.73 mollco 2 CO(NO3)3 + 3(NH4)2S → CO2S3 + 6 NHY NO3 ( Balanced reaction). Molar mass of Ca(NO3)₂ = 245 g/mol Weight of Co (NO3)3 = 79.29. or moles of CO (NO3), = 245 o weight = 79.2 mol - Molar mass 0.323 mol 80 CO(NO3)3 = on moles of NHUNO, 6x mol of NHU ND3, 0.323 mol 2 mol CO(NO3)3 -X Co (NO3)3 - 0.970 mol J ( NHỊ ), CO + NH3 + CO2 + H2O • 1 mol (NH4)2CO3 gives → 1 mol CO2 .: 4:01. i 4.01 mol CO2 molar mass CO₂ = 4400 g/mol .: Theoritical mass of CO2 Produced - moles x Molar mass = (4001 X 44.0) g -176.48] Scanned with CamScanner

2 N₂ Hu → 4NH3 + N₂ (Balanced equation) Weight of Nq = 28.0 g. Molar mass of N₂ = 2800 g/mol i moles of N₂ = weight = 1 mol - Molar mass -Ximol . N₂ moles of N2 Hy reacted - g mol N2 Hy reacted - Imol N2 Produced = 8 mol N₂ Hu A Molar mass N₂ Hy = 32.0 g/mol CS Scanned with weight of N2 Hy reacted = (2x 32.0)8 CamScanner = eng [9600 g Scar
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