Question

Practice with Stoichiometry Calculations - Problem Solving Workflow: You may be given either the number of grams or moles of chemical A and asked to determine ther the number of moles or grams of chemical B. Grams of A Moles of A Moles of B Grams of B 1. Convert from the number of 2. Convert from the number 3. Convert from the number of grams of A to the number of moles of moles of A to the number moles of 8 to the number of grams of A using the molar mass of A. of moles of Busing the of Busing the molar mass of B. coefficients of the balanced chemical equation. 8. How many grams of H, are required to produce 7.50 grams of ammonia NH.? Use the balanced equation (this time the equation is already balanced): N2(g) + 3H2(g) - 2NH (9) 9. If 54.7 grams of propane (CH) and 89.6 grams of oxygen (0) are available in the balanced combustion reaction below: C,He +50-300, +4H,0 a) Which reactant is limiting (show your work)? b) What is the theoretical yield of Co, in grams? Page 2 of 2

Answer 1

@ Met 3449) - IN4 (9) males of ammonia 0.44 mals. 7.50 17. To produce required a mals of Hz 2 mals of 4 → a mal Nha we I mal N43 o.nu mal Nuz 1 2x0.44 = 0.66 mals of ₂ moss of My = 0.66 x 2 = 1:32 go con ChB + 502 360 + 4400. - maks os 6g4o. 54.6 1.24 mals of o2 = 8 9 10 44 2.8 sina 1.24 md 24 mol of of 634d Gand require require : 1.24.5 6.2 = mal of oz 1:24 to react completely while we have only 2.8 mal al 02 WWW - Oz will be our limiting reactiant : .AISE (b) s mal of O2 → produce a mal of coz i mal os oz. →. 2 ml of co - 2.8 mal as a . - 2 x 2-8 mal os con = 1.68 mod Theoretical Yield of co= 1.68 X 44 gnimal ... Dasarecce = 73.92 m.