Question

Learning Goal: To understand how to use stoichiometry to convert between quantities of reactants and products in chemical equations Stoichiometry describes the quantitative relationships among the reactants and products of a balanced reaction by directly comparing mole ratios Stoichiometry can be used to convert mass, number of moles or number of particles between products and reactants, as shown in the flowchart displayed in the figure Review Constants Periodic Table To convert from a given quantity of one reactant or product to the quantity of another reactant or product • First convert the given quantity to moles. Use moler masses to convert masses to moles, and use Avogadro's number (6.02 x 10 particles per mole) to convert number of parlides to moles • Next, convert moles of the given reactant or product to moles of the desired reactant or product using the coefficients of the balanced chemical equation For example, in the chemical equation 2H +0,211, the coefficients tell us that 2 mol of the reacts with 1 mol of O, to produce 2 mol of H2O . Finally, convert moles of the desired reactant or product back to the desired units. Again, use molar masses to convert from molesto masses, and use Avogadro's number to convert from moles to number of particles number of mass Substance Avogadro's 1 1 molar mass 1 moles coefficients from balanced chemical equation moles Reaction of hydrogen and nitrogen to form ammonia Hydrogen gas. He reacts with nitrogen gas, Nto form ammonia gas, NH, according to the equation 3H2() + N()2NH3(x) NOTE: Throughout this tutorial use molar masses expressed to five significant figures. Substance B 1 mass Avogadro's number number of partides Part A How many moles of NH can be produced from 135 mol of Hy and excess N,? Express your answer numerically in moles. View Available Hints) ENG 9:40 PM 6/8/2020 Search

Answer 1

31 (9) + N2 (9) 2 Niylg) moles of 4 given = 13.5mal Acc. to stoichiometry of the reaction. Brool of the hooduces - 2 mol Nh 2 mol Nho Therefore 13.5 mol of the foreduces: 2 x 135 med Na : gmel nog Hence Land of produces 3 - gmol Ng Ang ☺ moles of Ne givers = 4.66 mol According to Stoichiometry of the reaction I mol Na foroduces Therefore 4.65 mol Ne produces: 2x4.65 mol Nih 2 mol Na 9.30 mol Nih Molar mass of Ny = 17.0 glmal mass of Nih poroduced: Moles x molar mass = 9.30x170 158.19 عمو جود ہےcon

Parta mass of the produced = 11.679 molar mass of why oglmal moles of Na poroduced = 11.67 -0.678 mal 17.0 17.0 2 ml Ning produced by 3 mal to I mal na foroduced by 3 melty 0.618 mal ning produced duced by 3 x 0.618 21.018 malih molar mass of 2.00 glmal mass of the needed moles x molar mass 2.00x 1.018 - 2.036 6 g mass of the given 3.39004g moles of h 3.398104 1.6958104 mol 2.00 1.695 mod X164 mol y produces 2 x 1.6958154 molt IND 1.13x154 mol Ning I mol of substance has 6.023x183 molecules of that substanie Therefore 1.13x104 mol Nh has 6.023 X1033 X 1.13x164 6.80x1019 molecules of NH3