Question

POGIL-Stoichiometry How do chemists use balanced chemical equations? got bit D 23 mosquitoes? 10 He got Mol-aria Why? Chemists use balanced chemical equations as a basis to calculate how much reactant is needed or product is formed in a reaction. This is called Stoichiometry- (stoi-key-ah-meh-tree) Another way of looking at it is using the mole ratio from the balanced equation and information about one compound in the reaction to determine information about another compound in the equation. A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation interpreted in terms of moles. In chemical calculations, mole ratios are used to convert between moles one thing and moles of another. Purpose: In this activity we will address the question: How do I convert between different chemical species in a given reaction? MODEL 1: Mole-to-Mole Stoichiometry (1-step) Example: mole-to-mole Question: Given the following equation: wod be 1N2 (g)+3 H2 (g) 2 NH, (g) How many moles of H2 are necded to produce 34.8 moles of NH,? Mole ratio Mole ratio Answer: 34.8 mol NH3 x 3 mol H 52,2mol H2 2 mol NHy 34.8 mol NH3 mol H2 52.2mol H 2 mol NH3 OR Key Questions: 1. What was the given in the example above? 3 molH come from? 2. Where did the 2 molNH Double check to see if 52.2 moles of H2 is the correct answer. SHOW the math below. 3.

Answer 1

| N2(g) + 3H2 19 2NH₂ (9) . Given example is A Reaction used in Haber Process for the Synthesis of Ammonia from Nitrogen and Hydrogen. 3 mol of H₂ Tomes from the following calculation a mol of NH3 for for a mol uts, No es moles of He Required = 2 I mol NHg = 3 mol of H₂ 1 2 mol of NH3 Now for 834.8 moles of NHg is being asked for 39.8 mol of NH3 = 3 mol of Hz ~ 34.8 mal of Nutty 2 mol of NH3 = 58.2 moles of H₂ © 14P + 502 -> 2205 0 Arronding to balanced Reaction 5 moles of a gives I mol of a gives - 3.4 moles of a gives a moles of hos a moles of Pros 5 moles of Oz 2 mol of Ros 34 mol of on 5 mol of o, X

= 1:36 of Ros gets formed moles For 5 moles of Or Number of moles of P Required = 4 for I mole of oz , Number of moles of p Requined = 1 / 2 Fox 30.1 moles of Qr i l u = p will = 24.08 moles of 1. be required (5 @ 2Al(s) + 3 lul62 (ap) — 246914)+36 () - Balanced chemical Repetion " Given 3 moles of tulla, No. of moles of Allla foormed = 2 for 1 mole of Gillz = 2 moles of Alles - for 6 mole of bulla = 2 xo moles of Alla from = u moles of Alleg - will form

for a moles of All too I mole of Alles Number of moles of Culla Regarred = 3 - 3 moles of lille 1 . Required for 4.5 moles of Alles - X9.5 = 6.75 moles of Culla - will be Reputred Maximum I have Miq Four questions are allowed to Answer. answered 5 questions just for your convenience. Thanks for asking question

Answer 2

Methane (CH4) and sulfur (S8) react to produce carbon disulfide and hydrogen sulfide, a liquid often used in

the production of cellophane