Question 9
Answer:
Part a
Required Minitab output is given as below:
One-way ANOVA: Yields versus Temperature
Analysis of Variance for Yields
Source DF SS MS F P
Temperat 2 148.56 74.28 10.53 0.011
Error 6 42.33 7.05
Total 8 190.89
P-value = 0.011
Part b
P-value < alpha value = 0.05
So, we reject the null hypothesis
There is sufficient evidence to conclude that mean yield differs with temperature.
Question 12
Answer:
Part a
Required Minitab output is given as below:
One-way ANOVA: Power versus Collector
Analysis of Variance for Power
Source DF SS MS F P
Collecto 3 1.6135 0.5378 17.35 0.000
Error 16 0.4960 0.0310
Total 19 2.1095
P-value = 0.000
Part b
P-value < alpha value 0.05
So, we reject the null hypothesis
There is sufficient evidence to conclude that the mean power differs for different collectors.
Using Minitab, List Hypothesis, Give P-values, and state the conclusion A certain chemical reaction was run...