Mean, µ = 2674
Standard deviation, σ = 508
Sample size, n = 108
1) Probability that the mean is greater than 2744, P(X̅ > 2744) =
= P( (X̅-μ)/(σ/√n) > (2744-2674)/(508/√108) )
= P(z > 1.432)
= 1 - P(z < 1.432)
Using excel function:
= 1 - NORM.S.DIST(1.432, 1)
= 0.0761
b) Probability that the mean is between 2543 and 2643, P(2543 < X < 2643) =
= P( (2543-2674)/508 < (X-µ)/σ < (2643-2674)/508 )
= P(-0.2579 < z < -0.061)
= P(z < -0.061) - P(z < -0.2579)
Using excel function:
= NORM.S.DIST(-0.061, 1) - NORM.S.DIST(-0.2579, 1)
= 0.0774
Question Question 4 of 6 (1.7 points) View problem in a pon-UR 6.3 Section Exercise 22...
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