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In a class on Statistics and Probability there at a total of 62 students enrolled (hint: n is irrelevant in this question). O

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Answer #1

Let S shows the event that student attend the class when there is exam or quizz. So we have

P(S') = 0.625, P(S) = 1- P(S') = 1 - 0.625 = 0.375

Now,

P(A|S') = 0.35, P(A | S) = 0.50

So the required probability is

P(S' | A) = [P(A|S')P(S')] / [ P(A|S')P(S') + P(A|S)P(S) ] = [0.35 * 0.625] / [ 0.35 *0.625 + 0.5 * 0.375 ] = 0.5385

Answer: 0.5385

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