Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: The null hypothesis states that there is no differences in opinion about smoking on college campuses for individuals with different smoking habits.
Alternative hypothesis: At least one of the null hypothesis statements is false.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square test for homogeneity.
Analyze sample data. Applying the chi-square test for homogeneity to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic. Based on the chi-square statistic and the degrees of freedom, we determine the P-value.
DF = (r - 1) * (c - 1) = (3 - 1) * (3 - 1)
D.F = 4
Er,c = (nr * nc) / n
Χ2 = 136
where DF is the degrees of freedom, r is the number of populations, c is the number of levels of the categorical variable, nr is the number of observations from population r, nc is the number of observations from level c of the categorical variable, n is the number of observations in the sample, Er,c is the expected frequency count in population r for level c, and Or,c is the observed frequency count in population r for level c.
The P-value is the probability that a chi-square statistic having 4 degrees of freedom is more extreme than 136.0.
We use the Chi-Square Distribution Calculator to find P(Χ2 > 136.00) = 0.0000.
Interpret results. Since the P-value (0.0000) is less than the significance level (0.05), we reject the null hypothesis.
From the above test we have sufficient evidence in the favor of the claim that there is differences in opinion about smoking on college campuses for individuals with different smoking habits.
Optional Chapter 5: Smoking on campus. In Febrnuary 2013, SurveyUSA interviewed a random sample 800 adults...