ΔH for the reaction
IF_{5}5(g) → IF_{3}3(g) + F_{2}2
is kJ, give the data below.
IF(g) + F_{2}2(g) → IF_{3}3(g) ΔH = -390 kJ IF(g) + 2F_{2}2(g) → IF_{5}5(g) ΔH = -745 kJ
Lets number the reaction as 0, 1, 2 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = +1 * (reaction 1) -1 * (reaction 2)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +1 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2)
= +1 * (-390) -1 * (-745)
= 355 KJ
Answer: 355 KJ
ΔH for the reaction IF_{5}5(g) → IF_{3}3(g) + F_{2}2 is kJ, give the data below. IF(g)...
ΔH for the reaction IF5 (g) → IF3 (g) + F2 (g) is ________ kJ, give the data below. IF (g) + F2 (g) → IF3 (g) ΔH = -390 kJ IF (g) + 2F2 (g) → IF5 (g) ΔH = -745 kJ
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Use Hess' Law to calculate the ΔH for the following reaction from the data given below. Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l) ΔH = _________ Na2CO3(s) → CO2(g) + Na2O(s) ΔH = 319.8 kJ 2NaCl(aq) + H2O(l) → 2HCl(aq) + Na2O(s) ΔH = +348.0 kJ