Hydrosulfuric acid, also known as hydrogen sulfide, is a diprotic acid. Its two-stage ionization is shown below:
H2S(aq) ⇆ H + + HS- (aq) Ka1 = 5.70x10-8
HS- (aq) ⇆ H + + S2- (aq) Ka2 = 1.0x 10-9
a. Calculate the concentration of HS- ion in a 0.222 M H2S solution.
b. Determine the pH of the solution.
c. Determine the S2- concentration.
Please write out all answers step-by-step :-)
Hydrosulfuric acid, also known as hydrogen sulfide, is a diprotic acid. Its two-stage ionization is shown...
Calculate the pH of a 0.982 M solution of hydrogen sulfide (H2S) Where: H2S (aq) -> H+ (aq) + HS- (aq) Ka1 = 1.0 x 10-7 HS- (aq) -> H+ (aq) + S2- (aq) Ka2 = 1.0 x 10-19 Enter your answer with at least 2 sig figs.
Calculate the pH and the equilibrium concentration of S2- in a 7.90×10-2 M hydrosulfuric acid solution, H2S (aq). For H2S, Ka1 = 1.0×10-7 and Ka2 = 1.0×10-19
answer all parts (a and b) please! Hydrogen sulfide (H2S) is a diprotic weak acid which can be used to selectively precipitate metal sulfide compounds from solution. The two deprotonation reactions of hydrogen sulfide are provided below along with their respective acid dissociation constants. H2S(ag) + H2O7) = HS (an) + H30+(aq) Kal = 1.0 * 10-7 HS (aq) + H2O) = 52 (ag) + H30 (29) K22=1 * 10-19 Imagine you have an aqueous solution buffered at pH 3...
The ionization constants for the diprotic acid H 2S are 1.0 x 10 -7 and 1.3 x 10 -13. H2S (aq) + H2O (l) <=> HS -(aq) + H3O +(aq) Ka = 1.0 x 10 -7 HS -(aq) + H2O (l) <=> S-2 (aq) + H3O +(aq) Ka = 1.3 x 10 -13 What is the equilibrium concentration of HS - in a 0.300 M solution of H2S?
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The ionization constants for the diprotic acid H 2S are 1.0 x 10 -7 and 1.3 x 10 -13. H2S (aq) + H2O (l) <=> HS -(aq) + H3O +(aq) Ka = 1.0 x 10 -7 HS -(aq) + H2O (l) <=> S-2 (aq) + H3O +(aq) Ka = 1.3 x 10 -13 What is the equilibrium concentration of HS - in a 0.300 M solution of H2S?
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