Calculate the pH of a 0.982 M solution of hydrogen sulfide (H2S) Where: H2S (aq) -> H+ (aq) + HS- (aq) Ka1 = 1.0 x 10-7 HS- (aq) -> H+ (aq) + S2- (aq) Ka2 = 1.0 x 10-19 Enter your answer with at least 2 sig figs.
Calculate the pH of a 0.982 M solution of hydrogen sulfide (H2S) Where: H2S (aq) ->...
Hydrosulfuric acid, also known as hydrogen sulfide, is a diprotic acid. Its two-stage ionization is shown below: H2S(aq) ⇆ H + + HS- (aq) Ka1 = 5.70x10-8 HS- (aq) ⇆ H + + S2- (aq) Ka2 = 1.0x 10-9 a. Calculate the concentration of HS- ion in a 0.222 M H2S solution. b. Determine the pH of the solution. c. Determine the S2- concentration. Please write out all answers step-by-step :-)
Calculate the pH and the equilibrium concentration of S2- in a 7.90×10-2 M hydrosulfuric acid solution, H2S (aq). For H2S, Ka1 = 1.0×10-7 and Ka2 = 1.0×10-19
answer all parts (a and b) please! Hydrogen sulfide (H2S) is a diprotic weak acid which can be used to selectively precipitate metal sulfide compounds from solution. The two deprotonation reactions of hydrogen sulfide are provided below along with their respective acid dissociation constants. H2S(ag) + H2O7) = HS (an) + H30+(aq) Kal = 1.0 * 10-7 HS (aq) + H2O) = 52 (ag) + H30 (29) K22=1 * 10-19 Imagine you have an aqueous solution buffered at pH 3...
Calculate the pH and [S2-] in a 0.15 M H2S solution. Assume Ka, 1.0 x 10-7, Ka2 = 1.0 x 10-19. pH s2-1 Need Help? Read It Supporting Materials ■ Supplemental Data Periodic Table Constants & Factors 7. -6.25 points ZumChemP8 7.E.098. Calculate the pH of a 3.4x 10-3 M solution of H2SO4
(2a) Calculate AG for reaction of hydrogen sulfide (gas) bubbling into an aqueous solution at the conditions given. The AGºrx = 45.6 kJ mol!. Assume the reaction takes place at 25°C. H2S(g, 0.75 atm) → H(aq, pH = 8.50) + HS (aq, 0.75 M)
Part ADetermine the pH during the titration of 29.2 mL of 0.274 M perchloric acid by 0.352 M potassium hydroxide at the following points: (1) Before the addition of any potassium hydroxide (2) After the addition of 11.4 mL of potassium hydroxide (3) At the equivalence point (4) After adding 28.8 mL of potassium hydroxide Part B Calculate the pH and the equilibrium concentrations of HS- and S2- in a 0.0590 M hydrosulfuric acid solution, H2S (aq). For H2S, Ka1...
A solution is prepared by adding 0.400 mol of hydrogen sulfide, H2S (pKa = 7.00) and 0.400 mol of the hydrogen sulfide ion, HS to 100.0 mL of water. Predict the final pH when 55.0 mL of 1.10 M NaOH is added to this buffer solution. Please explain. Thank you!
(25) An OPEN system contains hydrogen sulfide gas (H2S (g)...think rotten egg smell) at a concentration of PH2S 5x104 atm. The following two (2) equilibrium expressions apply (note: the term aq" refers to the liquid species of H2S) KH 0.08 M/atm (2) H2S (aq) H +HS H2S (aq) (1) H2S () K4 1070 a. Calculate the equilibrium H2S (aq) Concentration (in M) for this OPEN system and show the line on the Log C vs pH diagram. h Using the...
Credit for work! Thank you! 11) Hydrogen sulfide will react with water as shown in the following reactions. H2S(g) + H2O(l) ** 30"(aq) + HS-(aq) Ki-1.0 x 10-7 HS (aq) + H2O(l) + 30*(aq) + $9-(aq) K2-? H2S(8) + 2H2O(1) + 3O*(aq) + 52 (aq) Ks- 1.3 x 10-20 What is the value of K2? Show calculation steps.
Zinc sulfide (ZnS) has an increased solubility in acidic waters that is analogous to the increased solubility of PbS in acidic conditions. Using this information, and the K values in the following table, calculate the solubility of ZnS at a pH of 2.35. Process K 2.4 x 10-25 ZnS (s)Zn2(aq)S2- (aq) S2- (aq)H (aq)= HS (aq) HS (aq)H* (aq)= H2S (aq) 7.7 x 1012 1.0 x 107 Process K 2.4 x 10-25 ZnS (s)Zn2(aq)S2- (aq) S2- (aq)H (aq)= HS (aq)...