Question

What are the next two addresses? there are a total of 8 networks that can be created but only 6 are usable. What are the answers for the 5th and 6th subnet and their broadcast and Network address

nt 32 1611121 Question 27 Given an IP address of 19320 15.0 provide the informaltion below if we need a minmum of 28 unable hosts per s n mind that we wouid the to get the most number of Determine the Subnet Mask (255 255 255 224 Determine the CIDR 2 Detemine the network address and the broadcant address for each subnet NOTE Fu table as appleable ond คต "na-h@out the queles) to any "ngty spaces you mue hav" Address il Broadcast Address 9320 15.0 93 20 15.32 93 20.15.64 193 20 15.96 93 20.15128 193.20 15160 9320.15.192 193.20 15.224 93 2015311 93 20 15.63 93 20 1595 93 20 15127 93 20 15159 93.20.15 191 93 20.15.223 93 20.15.255 10 na na 13 Na 15 16 nswer 1

Answer 1

1)Major Network:192.20.15.0

2)CIDR /27 means every network contain 32 ip addresses.

3)Subnet Mask: 255.255.255.224

Cermine / TDR So evey neteork contci 32 TIP addresse,s i Subnet Mask: 55255-22 Network Addyess Brcadat Addres Subnet 92.20 15. 0 92 20 15.3 192-20-15. 32 192. 20- 15. 63 192 20-15.95 92- 20 57 42. 2o.15.64 4 92.20-15 96 92-20-15-12-8 92-2 -15 Isq 92-20-15.16 92-20. IS. 19I 구. 192.20.15-19 2. | 1922015-72る 92- 20 I5 2241220 S-255

7th and 8th networks are not useful.

your are specified /27 means 32-27=5 every network contain 2^5 = 32 ip addresses so the answer is already in your given question .

if any further explanations please comment me.