Question

Please explain every step in full detail with formulas included.

-/1.42 points SerCP11 8.1.OP.005. 2. My Notes The figure be low shows a horizontal bar, of length 4.8 m, with forces acting on it. A 30 N force acts at its left end, point O, in a direction down and to the left, 45° below horizontal. A 25 N force acts at its center, point C, in a direction up and to the right, 30° to the right of vertical. A 20 N force acts at the right end, in a direction down and to the right, 200 below horizontal 25 N 30 20° 45 2.4 m 10 N 4.8 m 30 N (a) What is the net torque (in N m) on the bar about an axis through O perpendicular to the page? N m magnitude direction -Select-- (b) What is the net torque (in N m) on the bar about an axis through C perpendicular to the page? N m magnitude ---Select- direction Need Help? Read It

Answer 1

25 N 2 450 2.4 m 2.4 m 30N algebic Sm point is eual to th The orque a bont a nat au the foy ees obbue that moment 6f Now the momant the prod ue f i's defined forea the the Lina 4 foree and the Pespendi culan a'stan ea from that point. Vaeto notation, In Y. F Sine . is the ds tan c the pt ine for ce from ro int Wher the the torque is reguied and the rgle betwean and F Contri bnton elue to ve oiu hara Abnt point the fore 30 N forr 25N and fos LON foree - ao S o nat tor que aoont the point o G 2.4X 25xsin 60 4.exIox Sin (-20) 35 54 N.m

oiu hava Point Contribuk'on C tho bAbowt tha no a for hak the tor que 25 N deve to for the 10 N -2 6 the for ce fer Ond 45 Please be coreful abont the angle Taking Teferenee auis the bar the ang la balouo it the is nagative Qnd in ansAi- eoeKwise Clocnuoise direetin is positive direetion One thing m direehion is mo Ye Po int C the the is ngative pocitve left iretion -tha and is actualy maative So 30N tha point Thuy nbany 3.4x 3ox Sin 45 the met about Ge 2.4x 16xSin (~20) X 24 Gn2o 50 91 8.21 G e 42.70 N, m