Question

Question 25 of 30 > A tightrope walker is walking between two buildings holding a pole with length L = 16.0 m, and mass mp-20.0 kg. The daredevil grips the pole with each hand a distance d = 0.500 m from the center of the pole. A bird of mass m 575 g lands on the very end of the left-hand side of the pole Assuming the daredevil applies upward forces with the left and right hands in a direction perpendicular to the pole, what magnitude of force Fieft and Fright must the left and right hand exert to counteract the torque of the bird? 2d x. Fieft- right Let the +x-axis point in the walking direction and pass through the center of the pole, and let the +z-axis point straight up. What are the directions of the torque vectors due to the bird, the left hand, and the right hand if the x-axis is the rotation axis? The torque vector due to the bird's weight points along the

Answer 1

Ans

Using right hand rule,

1) The torque vector due to bird's weight points along the -x direction.

2) The torque vector due to the force of the right points along the -x direction.

3) The torque vector due to the force of the left points along the +x direction.

Flefk Conditions o Fright equikibriorm = net torgue about A 二。 in Choosing clockuise foreve be posiive fo mp

2 2d 80( 20 2 heft = 1458975

l Nou VSing ΣΕ-o Net f orce in Vertica direction (20 +0.S7s) x9.80-145.847 s = Fright 55.73S N