Question

SS = 34 SS=30 SS = 64 -subjects design to in- mood inventory survey 20. A researcher uses a matched-subjects desir whether single people with pets are happie vestigate whether single people than singles without pets. A mood inventory is given to a group of 20-to 29-year-old non owners and a similar age group of pet owners. The pet owners are matched one to one with the non-ne owners for income, number of close friendships, and general health. The data follow: Pet Owner Matched Pair A Non-Pet Owner 12 14 10 nfidence interval to estimate a. Is there a significant difference in the mood scores for non-pet owners versus pet owners? Test wur a = .05 for two tails. b. Construct the 95% confidence interval to e the size of the mean difference in mood betwee the population of pet owners and the pop non-pet owners. (You should find that a mean difference of , = 0 is an a is consistent with the conclusion from esis test.) he population of acceptable value, which on from the hypoth- some evidence suggests that you are your test score if you rethink and change a ou are likely to improve ange answers on amine

Answer 1

Answer: a) Ho: PD = 0 Date: ----16/12/2019 H: HD #0 d = (-2 +1+ (-3) + 0 + (-6) + (-2)/6 = -2 Sd = sqrt(l-2+ 2)^2 + (1 + 2)^2 + (-3 + 2)^2 + (0 + 2)^2 + (-6 + 2)^2 + (-2 + 2)^2)/5) = 24495 (d - D/(Sg/V/m) The test statistic t = = (-2 - 0)/(24495/v6) = -20 At 0.05 significance level, the critical values are +/- to.025.5 = +/- 2571 Since the test statistic value is not less than the negative critical value(-2 > -2571), so we should not reject the null hypothesis. At 0.05 significance level, we cannot conclude that there is a significant difference in the mood scores for non-pet owners versus pet owners. b) The 95% confidence interval is d +/- to.025,5 * Sa/n = -2 +/- 2571*24495/V6 = -2 +/- 2571 = -4.571, 0.571