Question

11. What mass of nitrogen is contained in the ammonium nitrate prepared by treatment of 6.69g of aqueous ammonia with excess dilute nitric acid? NH3(aq) + HNO3(aq) + NH4NO3(aq) 12. How many millimoles of H2SO4 will react completely with 12.88 mL of 1.500M NaOH?

Answer 1

Page INH₂ Cag) + HNO, Lag) - NH 4 No, lag) Sence HNO is in excess, NH₂ es keiniting reactant Melar mass of NH₃ = 17.03g/mol Molar mass of NH, NO = 80043 g/mol 17.03g NH₃ gives 80.043 g NH₂ NO 6.699 Nhi will give 800439 X 6 69 g NHO NO 17.039 , 3.4 4 MH NO, 80.043 g NH, NO contains 2x 14.00 67 g N 31.44 NH ₂ NO contains 2x 14.0067 X 31.44 g N 80.043 = 11g N 12 Molarity of No OH = number of moles un volume I number of males MXU = 1.5 mol/L x 0.01288 L P = 0.01932 males H, SO + 2NaOH - No soy + 2H₂O znal Na Oll reacts with Imol H₂SO4 0.01932 mol NaOH will react with Imel 80.01932 mal. 2 mal = 0.00966 mol - 9.66 mmol