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10. Find the molarity of each type of ion in solution after 10.0 mL of 0.650M (NH4)3PO4 is diluted to 50.0 mL. 11. What mass
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Answer #1

10)

Given data,

Volume, V1 = 10 mL

V2 = 50 mL

Molarity , M1 = 0.650 M

Let us consider a reaction,

M1 x V1 = M2 x V2

0.650 x 10 = M2 x 50

M2 = 0.650 x 10 / 50

= 6.5 / 50

= 0.13 M

Therefore, the molarity of each type of ion is = 0.13 M

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