Question

Analysis of Vinegar EXPERIMENT NAME SECTION DATE POSTLABORATORY ASSIGNMENT 1. A standard nitric acid solution is prepared using 0.425 g of sodium carbonate, NaCO3. Find the molarity of the acid if 33.25 mL are required to reach a permanent endpoint. 2 HNO, (aq) + Na2CO3(s) + 2 NaNO3(aq) + H2O(l) + CO2(g) 2 H OT 2. A 10.0-ml sample of household ammonia solution required 27.50 mL of 0.241 M HNO3 for neutralization. Calculate (a) the molar concentration of the ammonia and (b) the mass/mass percent concentration of ammonia (17.04 g/mol). given a solution density of 0.985 g/mL. HNO3(aq) + NH3(aq) + NH4NO3(aq) (a) (b) 3. A 10.0 mL sample of calcium hydroxide solution required 26.85 mL of 0.225 M hydrochloric acid for neutralization. Calculate (a) the molar concentration of the base. 2 HCl(aq) + Ca(OH)2 (aq) + CaCl2(aq) + 2 H2O(l)

Answer 1

ID 2 Hnos talaq cos (3) »zalarlo slog) + the + coa col) o Imore Nazcos = amoly Hnos. Mors of Naecos = Weight horecaley weight = 04259 1067 More Molesot = 0.003899.9 = 0.0040 moly Halos = 2.X moles of Na2CO3. = MXVA 2X0.0040 M = 0.008 vainimeof acid = 33.2501 S = 33.25x10th ME 0.008 33.25xió? M=0:240 Molarity of acid Ctnog) = M = 0.24om. 2) Haloz cag) + NH3 Cay) » Nhunloz Coog) More iNo, a imore Nhy pentsalization Eruation Mini= MeV, at El had roles. Haloz . NH3. Molarity Mi = 0.241 M2 = 8 Volume Vi=27.50 V₂ = loomi

M Va T Molarity of NH₃ = M₂ 5 m X 27.50 10. DAT 0.24 1. a) = 6.6275 m TO = 0.66295 mass of Ammonia - motes thalarmuss ll = 0.66275 x 176004x141 of solution b) mass= 10. mi X dengity, = 10ATX 0.985 of = 9.85g. = 0.ll2g gSams. 100 Mass Percentage = mass of soluta not Mass of sointion = 0°11299 x100 goggy b. = 1.14"} 1 2HCl cas) et la cott), car) - call cay) + 2H2O Prove HCL S lemole la col), pentsalization Equation Mini a Mala

6 Hul CaCOH)2 Molarity EMI = 6.225 M₂ = Volume = Vi = 26.85MI. Vz= Mors n =2 mes 100m MINIT - Malah Me = MIN Yhz = - 0.225 MX 20185 X Imore. 2 mole x lo-orgt. 0.302 M = Imolarity of base = 0.302 en