Fundamental Theorem of Algebra:-
Given any positive integer and any choice of complex numbers such that the polynomial equation
has at least one solution .
Q9 6. Define Euclidean domain. 7. Let FCK be fields. Let a € K be a...
QUESTION C. (a) Let k be a field and let n be a positive integer. Define what is meant by a monomial ideal in k[x,...,zn]. 2. (b) State what it means for a ring R to be Noetherian. (c) State Hilbert's basis theorem. Give a proof of Hilbert's basis theorem using the fact if k is a field the polynomial ring kli,..., In] is Noetherian. 1S (a) Let k be a field and let n be a positive integer. Define...
Let F=Z_3 , the finite field with 3 elements. Let f(x) be an irreducible polynomial in F[x]. Let K=F[x]/(f(x)). We know that if r=[x] in K, then ris a root of f(x). Prove that f(r^3) is also a root of f(x). Which of the following are relevant ingredients for the proof? If a and b are in Z_3 then (a+b)^3=a^3+b^3 If g is an automorphism of K leaves g(r) is a root of f(x) The Remainder Theorem The Factor Theorem...
Let F=Z_3, the finite field with 3 elements. Let f(x) be an irreducible polynomial in F[x]. Let K=F[x]/(f(x)). We know that if r=[x] in K, then ris a root of f(x). Prove that f(r^3) is also a root of f(x). Which of the following are relevant ingredients for the proof? If a and b are in Z_3 then (ab)^3=(a^3)(b^3) The Remainder Theorem If a and b are in Z_3 then (a+b)^3=2^3+b^3 For all a in Z_3, a^3=a The first isomorphism...
Identifiy S3 with the group of S4 to 4 consisting of the permutations of (1,2,3,4 ) that maps a) Write down the elements of a subgroup H of S4 that is a conjugate of Ss but not S3 itself. (Hint: any such H wl have 6 elements) (b) How many subgroups of Sa are conjugates of Ss (including Ss itself)? (c)Let H be a subgroup of a group G. Show that Nc(H), the normalizer of H in G (d) What...
(4) This exercise outlines a proof that [21 KI 1//IIKİ whenever H and K are subgroups of a group G. (Note that HK-{hk | he H and k E K). The set HK is not always a subgroup of G.) Let -{hK | h є H). Define an action . . H x Ο Ο by the rule hị . ћК hihi. (You may assume that this is an action.) (a) Prove that OH(X). (b) Prove that HK-Hn K. (Here...
4. H ere are some True/False questions. If your answer is "TRUE", there is no need to justify your answer. If your answer is "FALSE", then you should justity your answer with a counterexample or explanation. There are also some "short-answer" questions. . A. (True-False). Every simple field extension of K is a finite field extension. . B. (True-False). Let R⑥ F be a field extension. Suppose that F is a of u E F, and splitting field for the...
1-5 theorem, state it. Define all terms, e.g., a cyclic group is generated by a single use a element. T encourage you to work together. If you find any errors, correct them and work the problem 1. Let G be the group of nonzero complex numbers under multiplication and let H-(x e G 1. (Recall that la + bil-b.) Give a geometric description of the cosets of H. Suppose K is a proper subgroup of H is a proper subgroup...
Answer Question 5 . Name: 1. Prove that if N is a subgroup of index 2 in a group G, then N is normal in G 2. Let N < SI consists of all those permutations ơ such that o(4)-4. Is N nonnal in sa? 3. Let G be a finite group and H a subgroup of G of order . If H is the only subgroup of G of order n, then is normal in G 4. Let G...
151 12. There are five multiple choice questions on this page. Three marks each. No partial marks. There is only one correct answer for each question. Circle the correct answer. (i) Consider the subgroup H = ([16]) of the additive group Z40- Which of the following left cosets of H is equal to [7] + H ? (A) (17) + H (B) (18) + H (C) [28] + H (D) [39] + H (E) [29] + H (ii) What is...
I have to use the following theorems to determine whether or not it is possible for the given orders to be simple. Theorem 1: |G|=1 or prime, then it is simple. Theorem 2: If |G| = (2 times an odd integer), the G is not simple. Theorem 3: n is an element of positive integers, n is not prime, p is prime, and p|n. If 1 is the only divisor of n that is congruent to 1 (mod p) then...