Question

I have to use the following theorems to determine whether or not it is possible for the given orders to be simple.

Theorem 1: |G|=1 or prime, then it is simple.

Theorem 2: If |G| = (2 times an odd integer), the G is not simple.

Theorem 3: n is an element of positive integers, n is not prime, p is prime, and p|n.

If 1 is the only divisor of n that is congruent to 1 (mod p) then no group of order n is simple.

Theorem 4: If n = p ^ k , where p is prime, then |G| = n implies G is not simple.

Theorem 5: n = ( p sub 1)(p sub 2), where (p sub 1) and (p sub 2) are both greater than 2 -- primes not simple.

I'm also going to include attachments of the book's verbatim on these theorems for clarity after the picture of the problem. I'm understanding the first two theorems, I'm not understanding how to use 3-5.

7.) Determine if it is possible for a group of the given order to be simple. Give more than just a one word explanation. a.)

Abelian simple groups of order less than 1000 and only 56 of order less than 1,000,000. In this chapter, we give a few theore

exercise 17 of Chapter 6 and exercise 7 of Chapter 12.) Hence, G is no simple. The next theorem is a broad generalization of

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