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(1 point) A function X(t) satisfies the differential equation di = (x − 2)(x – 5)²(x – 7)(x – 9)?. Compute the following limi

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1. dx = (x-2) (2-5² (x-7)(x-9) 2 dz Find critical point of alt) Put - +(x-2)(x-5) 2 (x-7)(x-9) 2-0 x=2, 5, 7, 9 of x42 . Thenт т xtt) is increasing in x> 9. +) Now x = 9 A(0,8 ) x = 7 & B (0,6) x = 5 ac (0,3.5 x=2 Now As we 3.5 and we If x (0)=305 caalt) - 5 lim too 200) = 6 we can see 8 lies between 7 and a and we know X(t) is increasing in and Bounded by 7 and 9 Tag g. I

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