H2CO3 dissociates as:
H2CO3 -----> H+ + HCO3-
5.9 0 0
5.9-x x x
Ka = [H+][HCO3-]/[H2CO3]
Ka = x*x/(c-x)
Assuming x can be ignored as compared to c
So, above expression becomes
Ka = x*x/(c)
so, x = sqrt (Ka*c)
x = sqrt ((4.5*10^-7)*5.9) = 1.629*10^-3
since c is much greater than x, our assumption is correct
so, x = 1.629*10^-3 M
So, [H+] = x = 1.629*10^-3 M
use:
pH = -log [H+]
= -log (1.629*10^-3)
= 2.788
Answer: 2.79
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