Question

2. The voltage across the 22.522 resistor in the circuit below is 90 V, positive at the upper terminal A 90 V 222.5 1 240 V 512 20.02 mise (a) Find the power dissipated in each resistor (b) Find the power delivered by the voltage source.

Answer 1

417 3 22:52 Da + old last, d so 2 I and Eisn loop 20+ Doel 1st loop 260

Assigning I & Iz en R&t & and loop respectuele. Current flowing in ord loop = current flowing in resistir 22.52 voltage avec le 22.52 Given go vi errent in od loop L5 90 = 4A 22-5 1= 4A]

Iwriting for Ist loop :- -240 + |1,-4) 4+ (1 - 12/20=0 -240 + 41, +6 + 2011-2012 = 0 249, -2012 –256 =0 - 0 (writing for and loop :- 19-4 )S + 1215 +(12-21) 20 =0 $19-20 + 1812 + 2012 – 2011=0 401, 4201, -20 = 0 - solving (7 86 1 2 = 19 AY I P2 = 10 A power dimeßated Soy Heelstoke 28-= 472 x 22.5 - 3606 Awer dimripated by heliffor 42 = (19_4)2X4.*. = goow Power dinspated by helistor 62 = (10-4)² xS = 180w Power demo fated by Stellector ise = (10)2x15 = 1500 W Power denipated by resistor 200 =(19-10j? X20 = 1620 W @Yotal Bower disse fated = 360 +900 + 180 wt isoa +1620 w =... 4560w

source 6 Power delivered by voltage source lovere les = VIL 240x 19 = 4560 W