Question

Calculate the rpm needed for a motor with 280 ft-lbs of torque to drive a permanently installed horizontal 42"-belt that is one mile long. The production rate of the system should be 500 tph when the belt moves 308 fpm. The speed reduction mechanism used is a v-belt with sheaves, and the material density is 150 lbs/ft?

Answer 1

Page no: Date: / force = lt.g (mitmb) mi Soo (tph ) 808 (Fpm - Soox1000 3600 3088 3048 m = 89.03 1 Mb = (1 mile xy21x1)x f. =(1.0688x1609.34x))x 150X 453 .304 8 - Mb = 382454.26 kg. Put the value of mid mb in ean torle 5x9.818[89.03 + 382454.26 - 1876374 M. P = fx vel. → 1876374X 308 X 3048 293585).16 MM 60 Pa Txw. W= P 2935851.16 - 379.6813 T 28083048x-4535X9.8) W=7732.435 W=27TH = wx60 - 7732.425X66 60 - 2T 2XT N = 73809.612