Question

1. (15 Pts.) What is the maximum number of electrons that can be emitted if a potassium surface of work function 2.56 eV absorbs 5.00× 103 J of radiation at a wavelength of 355 nm? (10 point for work shown, 2 point for units, 3 point for correet answer). (15 Pts.) What is the velocity of the electrons emitted? (10 point for work shown, 2 point fo point for correct answer). r units, 3 2.

Answer 1

ven data , wavdlenath355 nm 355 x 10-9 m work-function ( 2.56 eV Energy CE) 5 xo-3 J lhe eney of peo elecbron Ee releasinq at a wavelength of 355 nm is , (6.626 x 10-34 Js ) ( 3x108 m/s ) 355 x 10-9 m 5.60 x 109j he maximum number N of electrons emitted is, 20 Upon Substitulion, N 5x oJ 5-60 x1o-19 j r 38.94 x1015 electrons

Converting unit of work function (ф) to Joules (J) : I e v 4.096 x 10-19 j Maximum Kinetic en emitted elertron is . Kmax - Ee こ1-504X10-19 J b) The velocity of emited electron t 2 2x (i.504 x lo-19 j 9.1 X lo-31 k Velocity o f emitted electron s 5.74 x lo5 m/s .

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