E = (254 kJ x 103J/mol)/(6.022 x 1023 electron/mol) = 4.218 x 10-19 J/electron
λ = hc/E = (6.626 x 10-34J.s) x (3 X 108m/s)/(4.218 x 10-19J/ele) = 4.71 x 10-7m
λ = 471 nm per photon, under the assumption that each phonton will cause the electron to overcome the workfunction of the metal and get ejected.
17. It takes 254 kJ/mol to eject electrons from a certain metal surface. What is the...
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