Question

A car makes a sharp 90ᵒ turn in the form of an ellipse. It comes into the ellipse at a speed V along the semi-major axis A and exits the turn along the semi-minor axis B. The car turns with a constant angular speed the entire way through. What is the acceleration vector in relative coordinates half way through the turn (as measured by angle)?

(2) A car makes a sharp 90° turn in the form of an ellipse. It comes into the ellipse at a speed V along the semi-major axis A and exits the tum along the semi-minor axis B. The car turns with a constant angular speed the entire way through. What is the acceleration vector in relative coordinates half way through the turn (as measured by angle)? 2/12 /1-) +2ABA | Answer: å = @* (****) (4 ** ) ))

Answer 1

0 Answer From the ATO B as in figure 90 Angle us The Constant Angular Velocity Tangential Acceleration is zero And the only Centecipetal Acceleration will work. Hence acceleration & faktion m = ung = Mg

'Hence Component will be z =- ug cos usi - ug sinus j wet where ! M=Coefficut of friction.