1)P(2nd ace |first ace) =3/51 =0.06 (since there remain 3 ace out of 51 cards, if first is ace)
2)
P(sum is 4) =3/36 =0.08 (since there are 3 outcomes (2,2),(!,3),(3,1)) out of 36 where sum is 4)
3)
Probability =P(detected)*P(shot down |Detected) =0.9*0.8 =0.72
i need help with these three probability questions, please. thanks. Given a standard deck of cards....
Practice questions for BIO 340 (Exam 2) I need help with these questions Please. WILL GIVE GOOD RATING 1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...