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Problem #2: In the circuit shown below use Thevenins equivalent circuit method to determine: a) The output current lo b) How
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- @ using theven in theorem &- To find Rth :- → Short circuit - voltage source Open circuit - cwegent source » circuit is, 1.- (123Vih) + 2 md + 24-Vith so - 4k :. 4 (-12. + Voth ) +418 + 6( 24 – Uth)=0 : -48 +4448 +48 +144 - 6 Vth 20 -2 Vith = -144© Max Power delivered to load is, Pmax= thx Io = 72 x 6 mA % Pmax = 432 mw

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