Question

Please answer Part B.

What volume of O2 at 988 mmHg and 33 C is required to synthesize 17.5 mol of NO? Express your answer numerically in liters. View Available Hint(s) volume of O2 = 423 L Submit Previous Answers All attempts used; correct answer displayed You have calculated the theoretical volume of O2 needed to produce 17.5 mol of NO. However, in the industrial production of NO, oxygen is added in excess of this amount. Part B What volume of H2O(g) is produced by the reaction under the same conditions? Express your answer numerically in liters. View Available Hint(s)

Answer 1

Given

Volume of O2 is 423 L

17.5 mol NO2

988 mmHg pressure

33 degree Celsius

We know that R is 62.36367 L mmHg/ K mol

Equation is

4 NH3 + 5 O2 → 4 NO + 6 H2O.

Now

(17.5 mol NO) x (6 mol H2O / 4 mol NO) = 26.25 mole H2O

Volume of H2O(g) will be

V = nRT / P

= (26.25 mol) * (62.36367 L mmHg/K mol) * (33 + 273) K / (988

mmHg)

= 507 L H2O(g)