The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH...
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH3(g)+?O2(g)→?NO(g)+?H2O(g) Part A What volume of O2 at 684 mmHg and 41 ∘C is required to synthesize 19.0 mol of NO? Express your answer to three significant figures and include the appropriate units. volume of O^2=
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH3(g)+?O2(g)→?NO(g)+?H2O(g) What volume of O2 at 798 mmHg and 41 ∘C is required to synthesize 12.5 mol of NO? Express your answer to three significant figures and include the appropriate units.
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH3(g)+?O2(g)→?NO(g)+?H2O(g) What volume of O2 at 912 mmHg and 41 ∘C∘C is required to synthesize 24.5 mol of NO? 750 mmHg = 1 bar R = 0.08314 L bar mol-1 K-1 Express your answer numerically in litres.
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: NH3(g)+?O2(g)→?NO(g)+?H2O(g) What volume of O2 at 722 mmHg and 27 ∘C is required to synthesize 17.5 mol of NO?
What volume of O2 at 684 mmHg and 39 ∘C is required to synthesize 19.0 mol of NO? Express your answer to three significant figures and include the appropriate units. The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (02) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH3 (g)+?02(g)?NO (g)+?H, O (g)
Fall19 Assignments MC8 MC8 <MC8 ± The Ideal Gas Law and Stoichiometry Reviow | Cons The industrial production of nitric acid (HNOs) is a multstep process. The first step is the oxidation of ammonia (NHa) over a catalyst with excess oxygen (Os) to produce nitrogen monoxide (NO gas as shown by the unbalanced equation given Part A What volume of O, at 684 mmHg and 21 C is required to synthesize 14.0 mol of NO? here 7NH (R)+70,() 7NO(g)+?H,O(g) Express...
The first step in the industrial production of nitric acid is reacting ammonia with oxygen according to the unbalanced equation: NH3(g) + O2(g) → NO(g) + H2O(g) How many liters of NH3(g) at 850.oC and 5.00 atm are required to react with 32.0 g of O2? 0.811g of KClO3 is decomposed as follows: 2KClO3(s) → 2KCl(s) + 3O2(g) The O2 is collected over water at 28 oC and 765 torr. What is the volume of water displaced in this measurement,...
HOMWOPR Chapter II The Ideal Gas Law and Stoichiometry 14 of 15 Review Constants Periodic Table What volume of O, at 836 mmHg and 37 °C is required to synthesize 10.0 mol of NO? Express your answer to three significant figures and include the appropriate units. The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (Os) to produce nitrogen monoxide (NO) gas as...
The first step in industrial nitric acid (HNO3) production is the catalyzed oxidation of ammonia (NH3). Without the catalyst the following reaction predominates: 4NH3(g) + 3O2(g) ⇔ 2N2(g) + 6H2O(g). When 0.0150 mol each of NH3(g) and O2(g) are placed in a 1.00 L container at a certain temperature the N2(g) concentration at equilibrium is 1.96x10-3 M. Fill in the following ICE table and calculate the resulting KC. NH3(9) 02(9) N2(9) H20(9) Initial (1) 015 mol mol .015 Number Number...
What volume of H2O(g) is produced by the reaction under the same conditions? What volume of O2 at 798 mmHg and 41 °C is required to synthesize 12.5 mol of NO? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) volume of O2 = 384 L Previous Answers Answer Requested You have calculated the theoretical volume of O2 needed to produce 12.5 mol of NO. However this amount Part B What volume of H2O(g)...